99x+9x^2=108

Solution for 99x+9x^2=108 equation:

99x+9x^2=108

We move all terms to the left:

99x+9x^2-(108)=0

a = 9; b = 99; c = -108;
Δ = b2-4ac
Δ = 992-4·9·(-108)
Δ = 13689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{13689}=117$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(99)-117}{2*9}=\frac{-216}{18}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(99)+117}{2*9}=\frac{18}{18}
=1
$